HMMT 二月 2016 · 冲刺赛 · 第 11 题
HMMT February 2016 — Guts Round — Problem 11
题目详情
英文原题
- [ 7 ] Define φ ( n ) as the product of all positive integers less than or equal to n and relatively prime ton . Compute the remainder when
∑
!
φ ( n )
2 ≤ n ≤ 50
gcd( n, 50)=1
is divided by 50.
解析
英文解析
- [ 7 ] Define φ ( n ) as the product of all positive integers less than or equal to n and relatively prime ton . Compute the remainder when
∑
!
φ ( n )
2 ≤ n ≤ 50
gcd( n, 50)=1
is divided by 50.
Proposed by: Evan Chen
Answer: 12
!
First, φ ( n ) is even for all odd n , so it vanishes modulo 2.
! ! !
To compute the remainder modulo 25, we first evaluate φ (3) + φ (7) + φ (9) ≡ 2 + 5 · 4 + 5 · 3 ≡ 12
(mod 25). Now, for n ≥ 11 the contribution modulo 25 vanishes as long as 5 - n .
We conclude the answer is 12.