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HMMT 十一月 2015 · 团队赛 · 第 2 题

HMMT November 2015 — Team Round — Problem 2

专题
Contest Math / 竞赛数学
难度
L3
来源
HMMT

题目详情

英文原题

  1. [ 3 ] Bassanio has three red coins, four yellow coins, and five blue coins. At any point, he may give
    Shylock any two coins of different colors in exchange for one coin of the other color; for example, hemay give Shylock one red coin and one blue coin, and receive one yellow coin in return. Bassaniowishes to end with coins that are all the same color, and he wishes to do this while having as manycoins as possible. How many coins will he end up with, and what color will they be?
解析

英文解析

  1. [ 3 ] Bassanio has three red coins, four yellow coins, and five blue coins. At any point, he may give
    Shylock any two coins of different colors in exchange for one coin of the other color; for example, hemay give Shylock one red coin and one blue coin, and receive one yellow coin in return. Bassaniowishes to end with coins that are all the same color, and he wishes to do this while having as manycoins as possible. How many coins will he end up with, and what color will they be?
    Proposed by: Yang Liu
    Answer: 7 yellow coins
    Let r, y, b denote the numbers of red, yellow, and blue coins respectively. Note that each of the threepossible exchanges do not change the parities of y − r, b − y, or b − r , and eventually one of thesedifferences becomes zero. Since b − r is the only one of these differences that is originally even, it must be the one that becomes zero, and so Bassanio will end with some number of yellow coins. Furthermore,
    Bassanio loses a coin in each exchange, and he requires at least five exchanges to rid himself of theblue coins, so he will have at most 12 − 5 = 7 yellow coins at the end of his trading.
    It remains to construct a sequence of trades that result in seven yellow coins. First, Bassanio willexchange one yellow and one blue coin for one red coin, leaving him with four red coins, three yellowcoins, and four blue coins. He then converts the red and blue coins into yellow coins, resulting in
    7 yellow coins , as desired.