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HMMT 十一月 2015 · 冲刺赛 · 第 31 题

HMMT November 2015 — Guts Round — Problem 31

专题
Contest Math / 竞赛数学
难度
L3
来源
HMMT

题目详情

英文原题

  1. [ 17 ] Two random points are chosen on a segment and the segment is divided at each of these twopoints. Of the three segments obtained, find the probability that the largest segment is more thanthree times longer than the smallest segment. x
解析

英文解析

  1. [ 17 ] Two random points are chosen on a segment and the segment is divided at each of these twopoints. Of the three segments obtained, find the probability that the largest segment is more thanthree times longer than the smallest segment.
    Proposed by: Sam Korsky
    Answer:27
    We interpret the problem with geometric probability. Let the three segments have lengths x, y, 1 − x − y 35
    and assume WLOG that x ≥ y ≥ 1 − x − y . The every possible ( x, y ) can be found in the triangle
    ( )
    1 1 1 1 2 1
    determined by the points , , ( , ), (1 , 0) in R , which has area . The line x = 3(1 − x − y )
    3 3 2 2 12
    ( ) ( )
    3 3 3 1
    intersects the lines x = y and y = 1 − x − y at the points , and , Hence x ≤ 3(1 − x − y )
    7 7 5 5
    ( ) ( ) ( )
    1 1 3 3 3 1 2
    if ( x, y ) is in the triangle determined by points , , , , , which by shoelace has area .
    3 3 7 7 5 5 105
    Hence the desired probability is given by
    1 2
    27−
    12 105
    1=
    1235 x