HMMT 十一月 2015 · 冲刺赛 · 第 3 题

HMMT November 2015 — Guts Round — Problem 3

[ 5 ] A parallelogram has 2 sides of length 20 and 15. Given that its area is a positive integer, find the minimum possible area of the parallelogram. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . HMMT November 2015, November 14, 2015 — GUTS ROUND Organization Team Team ID#

解析

[ 5 ] A parallelogram has 2 sides of length 20 and 15. Given that its area is a positive integer, find the minimum possible area of the parallelogram. Proposed by: Yang Liu Answer: 1 The area of the parallelogram can be made arbitrarily small, so the smallest positive integer area is 1.