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HMMT 二月 2015 · 冲刺赛 · 第 4 题

HMMT February 2015 — Guts Round — Problem 4

专题
Contest Math / 竞赛数学
难度
L3
来源
HMMT

题目详情

英文原题

  1. [ 4 ] Consider the function z ( x, y ) describing the paraboloid
    2 2
    z = (2 x − y ) − 2 y − 3 y.
    Archimedes and Brahmagupta are playing a game. Archimedes first chooses x . Afterwards, Brahmagupta chooses y . Archimedes wishes to minimize z while Brahmagupta wishes to maximize z .
    Assuming that Brahmagupta will play optimally, what value of x should Archimedes choose?
    HMMT FEBRUARY 2015, 21 FEBRUARY 2015 — GUTS ROUND
    Organization Team Team ID#
解析

英文解析

  1. [ 4 ] Consider the function z ( x, y ) describing the paraboloid
    2 2
    z = (2 x − y ) − 2 y − 3 y.
    Archimedes and Brahmagupta are playing a game. Archimedes first chooses x . Afterwards, Brahmagupta chooses y . Archimedes wishes to minimize z while Brahmagupta wishes to maximize z .
    Assuming that Brahmagupta will play optimally, what value of x should Archimedes choose?
    Answer: − Viewing x as a constant and completing the square, we find that 3
    2 2 28
    z = 4 x − 4 xy + y − 2 y − 3 y
    2 2 = − y − (4 x + 3) y + 4 x
    ( ) ( )
    2 2
    4 x + 3 4 x + 3 = − y + + + 4 x .2
    2 2
    4 x +3
    Bhramagupta wishes to maximize z , so regardless of the value of x , he will pick y = − . Theexpression for z then simplifies to 2
    z = 8 x + 6 x + .29
    Guts 4
    Archimedes knows this and will therefore pick x to minimize the above expression. By completing the square, we find that x = − minimizes z .3
    Alternatively, note that z is convex in x and concave in y , so we can use the minimax theorem to switch 8
    the order of moves. If Archimedes goes second, he will set x = to minimize z , so Brahmagupta willy
    2 3 32
    maximize − 2 y − 3 y by setting y = − . Thus Archimedes should pick x = − , as above.
    4 8