HMMT 二月 2015 · 冲刺赛 · 第 4 题
HMMT February 2015 — Guts Round — Problem 4
题目详情
英文原题
- [ 4 ] Consider the function z ( x, y ) describing the paraboloid
2 2
z = (2 x − y ) − 2 y − 3 y.
Archimedes and Brahmagupta are playing a game. Archimedes first chooses x . Afterwards, Brahmagupta chooses y . Archimedes wishes to minimize z while Brahmagupta wishes to maximize z .
Assuming that Brahmagupta will play optimally, what value of x should Archimedes choose?
HMMT FEBRUARY 2015, 21 FEBRUARY 2015 — GUTS ROUND
Organization Team Team ID#
解析
英文解析
- [ 4 ] Consider the function z ( x, y ) describing the paraboloid
2 2
z = (2 x − y ) − 2 y − 3 y.
Archimedes and Brahmagupta are playing a game. Archimedes first chooses x . Afterwards, Brahmagupta chooses y . Archimedes wishes to minimize z while Brahmagupta wishes to maximize z .
Assuming that Brahmagupta will play optimally, what value of x should Archimedes choose?
Answer: − Viewing x as a constant and completing the square, we find that 3
2 2 28
z = 4 x − 4 xy + y − 2 y − 3 y
2 2 = − y − (4 x + 3) y + 4 x
( ) ( )
2 2
4 x + 3 4 x + 3 = − y + + + 4 x .2
2 2
4 x +3
Bhramagupta wishes to maximize z , so regardless of the value of x , he will pick y = − . Theexpression for z then simplifies to 2
z = 8 x + 6 x + .29
Guts 4
Archimedes knows this and will therefore pick x to minimize the above expression. By completing the square, we find that x = − minimizes z .3
Alternatively, note that z is convex in x and concave in y , so we can use the minimax theorem to switch 8
the order of moves. If Archimedes goes second, he will set x = to minimize z , so Brahmagupta willy
2 3 32
maximize − 2 y − 3 y by setting y = − . Thus Archimedes should pick x = − , as above.
4 8