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HMMT 二月 2015 · 冲刺赛 · 第 12 题

HMMT February 2015 — Guts Round — Problem 12

专题
Contest Math / 竞赛数学
难度
L3
来源
HMMT

题目详情

  1. [ 6 ] For integers a, b, c, d , let f ( a, b, c, d ) denote the number of ordered pairs of integers ( x, y ) ∈
    { 1 , 2 , 3 , 4 , 5 } such that ax + by and cx + dy are both divisible by 5. Find the sum of all possible 2
    values of f ( a, b, c, d ).
    HMMT FEBRUARY 2015, 21 FEBRUARY 2015 — GUTS ROUND
    Organization Team Team ID#
    3 2

英文原题

[ 6 ] For integers a, b, c, d , let f ( a, b, c, d ) denote the number of ordered pairs of integers ( x, y ) ∈
{ 1 , 2 , 3 , 4 , 5 } 2 such that ax + by and cx + dy are both divisible by 5. Find the sum of all possible
values of f ( a, b, c, d ).
. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .
HMMT FEBRUARY 2015, 21 FEBRUARY 2015 — GUTS ROUND
Organization Team Team ID#

解析

英文解析

  1. [ 6 ] For integers a, b, c, d , let f ( a, b, c, d ) denote the number of ordered pairs of integers ( x, y ) ∈
    { 1 , 2 , 3 , 4 , 5 } such that ax + by and cx + dy are both divisible by 5. Find the sum of all possible 2
    values of f ( a, b, c, d ).
    Answer: 31 Standard linear algebra over the field F (the integers modulo 5). The dimension ofthe solution set is at least 0 and at most 2, and any intermediate value can also be attained. So the 5
    answer is 1 + 5 + 5 = 31.2
    This also can be easily reformulated in more concrete equation/congruence-solving terms, especiallysince there are few variables/equations.
    3 2