返回题库

HMMT 十一月 2014 · THM 赛 · 第 2 题

HMMT November 2014 — THM Round — Problem 2

专题
Contest Math / 竞赛数学
难度
L3
来源
HMMT

题目详情

英文原题

  1. Find the smallest positive integer n such that, if there are initially 2 n townspeople and 1 goon, thenthe probability the townspeople win is greater than 50%.
解析

英文解析

  1. Find the smallest positive integer n such that, if there are initially 2 n townspeople and 1 goon, thenthe probability the townspeople win is greater than 50%.
    Answer: 3 We instead consider the probability the goon wins. The game clearly must last n days.
    The probability the goon is not sent to jail on any of these n days is then
    2 n 2 n − 2 2
    · · · · · · .
    2 n + 1 2 n − 1 3
    4 2 8 1 6 8 16 1
    If n = 2 then the probability the goon wins is · = > , but when n = 3 we have · = < ,
    5 3 15 2 7 15 35 2
    so the answer is n = 3.
    Alternatively, the let p be the probability that 2 n townspeople triumph against 1 goon. There is anchance that the goon is jailed during the first morning and the townspeople win. Otherwise, the 1
    2 n +1
    goon eliminates one townperson during the night. We thus have 2 n − 2 townspeople and 1 goon left,
    so the probability that the town wins is p . We obtain the recursionn − 1
    1 2 np = + p .
    n n − 1
    2 n + 1 2 n + 1
    1 7 1
    By the previous question, we have the initial condition p = . We find that p = < and
    1 2
    3 15 2
    19 1
    p = > , yielding n = 3 as above.
    35 23