HMMT 十一月 2014 · 冲刺赛 · 第 27 题
HMMT November 2014 — Guts Round — Problem 27
题目详情
英文原题
- [ 13 ] In triangle ABC , let the parabola with focus A and directrix BC intersect sides AB and AC at
A and A , respectively. Similarly, let the parabola with focus B and directrix CA intersect sides BC
1 2
and BA at B and B , respectively. Finally, let the parabola with focus C and directrix AB intersect
1 2
sides CA and CB at C and C , respectively.
1 2
If triangle ABC has sides of length 5, 12, and 13, find the area of the triangle determined by lines
A C , B A and C B .
1 2 1 2 1 2
HMMT NOVEMBER 2014, 15 NOVEMBER 2014 — GUTS ROUND
Organization Team Team ID#
− 1 3 2
解析
英文解析
- [ 13 ] In triangle ABC , let the parabola with focus A and directrix BC intersect sides AB and AC at
A and A , respectively. Similarly, let the parabola with focus B and directrix CA intersect sides BC
1 2
and BA at B and B , respectively. Finally, let the parabola with focus C and directrix AB intersect
1 2
sides CA and CB at C and C , respectively.
1 2
If triangle ABC has sides of length 5, 12, and 13, find the area of the triangle determined by lines
A C , B A and C B .
1 2 1 2 1 2
6728
Answer: By the definition of a parabola, we get AA = A B sin B and similarly for the
1 1
3375
AB AC
2 1
other points. So = , giving B C ‖ BC , and similarly for the other sides. So DEF (WLOG,
2 1
AB ACin that order) is similar to ABC . It suffices to scale after finding the length of EF , which is
B C − B F − EC
2 1 2 1
The parallel lines also give us B A F ∼ BAC and so forth, so expanding out the ratios from these
2 1
similarities in terms of sines eventually gives
∏ ∑
2 sin A + sin A sin B − 1
cyc cyc eF
∏
BC (1 + sin A )=
Plugging in, squaring the result, and multiplying by K = 30 gives the answer.cyc
Guts Round aBC − 1 3 2