HMMT 十一月 2014 · GEN 赛 · 第 6 题
HMMT November 2014 — GEN Round — Problem 6
题目详情
英文原题
- Let ABC be a triangle with AB = 5, AC = 4, BC = 6. The angle bisector of C intersects side AB at
X . Points M and N are drawn on sides BC and AC , respectively, such that XM ‖ AC and XN ‖ BC .
Compute the length M N .
解析
英文解析
- Let ABC be a triangle with AB = 5, AC = 4, BC = 6. The angle bisector of C intersects side AB at
X . Points M and N are drawn on sides BC and AC , respectively, such that XM ‖ AC and XN ‖ BC .
Compute the length M N .
√
3 14
Answer: By Stewart’s Theorem on the angle bisector,
( )5
AB2
CX = AC · BC 1 −2
AC + BC
Thus,
( )
CX = 4 · 6 1 − = 18252
Since XM ‖ AC and XN ‖ BC , we produce equal angles. So, by similar triangles, XM = XN =10
4 · 6 12 = .
10 5
Moreover, triangles M CX and N CX are congruent isosceles triangles with vertices M and N , respectively. Since CX is an angle bisector, then CX and M N are perpendicular bisectors of each other.
Therefore,
( )
12 1262
2 2 2
M N = 4( XN − ( CX/ 2) ) = 4 · − 18 =
5 25
√and
3 14
M N = 5