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HMMT 二月 2014 · 冲刺赛 · 第 9 题

HMMT February 2014 — Guts Round — Problem 9

专题
Contest Math / 竞赛数学
难度
L3
来源
HMMT

题目详情

英文原题

  1. [ 6 ] Compute the side length of the largest cube contained in the region
    2 2 2
    { ( x, y, z ) : x + y + z  25 and x 0 }
    of three-dimensional space.
解析

英文解析

  1. [ 6 ] Compute the side length of the largest cube contained in the region
    2 2 2
    { ( x, y, z ) : x + y + z ≤ 25 and x ≥ 0 }
    of three-dimensional space.
    √
    5 6
    Answer: The given region is a hemisphere, so the largest cube that can fit inside it has oneface centered at the origin and the four vertices of the opposite face on the spherical surface. Let the 3
    side length of this cube be s . Then, the radius of the circle is the hypotenuse of a triangle with side
    √ √
    2 6
    lengths s and s . So, by the Pythagorean Theorem, the radius equals s . Since the radius of the
    2 2
    √
    5 6
    hemisphere is 5, the side length of the cube is . 3