HMMT 二月 2014 · 冲刺赛 · 第 36 题
HMMT February 2014 — Guts Round — Problem 36
题目详情
英文原题
- [ 25 ] We have two concentric circles C and C with radii 1 and 2, respectively. A random chord of C
1 2 2
is chosen. What is the probability that it intersects C ?
m 1
Your answer to this problem must be expressed in the form , where m and n are positive integers. Ifn
25 · Xyour answer is in this form, your score for this problem will be b c , where X is the total number ofteams who submit the answer (including your own team), and Y is the total number of teams whom ynsubmit a valid answer. Otherwise, your score is 0. (Your answer is not graded based on correctness,
whether your fraction is in lowest terms, whether it is at most 1, etc.)
HMMT 2014, 22 FEBRUARY 2014 — GUTS ROUND
Organization Team Team ID#
解析
英文解析
- [ 25 ] We have two concentric circles C and C with radii 1 and 2, respectively. A random chord of C
1 2 2
is chosen. What is the probability that it intersects C ?
m 1
Your answer to this problem must be expressed in the form , where m and n are positive integers. Ifn
25 · Xyour answer is in this form, your score for this problem will be b c , where X is the total number ofteams who submit the answer (including your own team), and Y is the total number of teams whom ynsubmit a valid answer. Otherwise, your score is 0. (Your answer is not graded based on correctness,
whether your fraction is in lowest terms, whether it is at most 1, etc.)
Answer: N/A The question given at the beginning of the problem statement is a famous problemin probability theory widely known as Bertrand’s paradox. Depending on the interpretation of thephrase “random chord,” there are at least three different possible answers to this question:
• If the random chord is chosen by choosing two (uniform) random endpoints on circle C andtaking the chord joining them, the answer to the question is 1 / 3.2
• If the random chord is chosen by choosing a (uniformly) random point P the interior of C (otherthan the center) and taking the chord with midpoint P , the answer to the question becomes 1 / 4.2
• If the random chord is chosen by choosing a (uniformly) random diameter d of C , choosing apoint P on d , and taking the chord passing through P and perpendicular to d , the answer tothe question becomes 1 / 2. (This is also the answer resulting from taking a uniformly randomhorizontal chord of C .)
You can read more about Bertrand’s paradox online at http://en.wikipedia.org/wiki/Bertrand_2
paradox_(probability) . We expect that many of the valid submissions to this problem will be equalto 1 / 2 , 1 / 3, or 1 / 4.
However, your score on this problem is not based on correctness, but is rather proportional to the number of teams who wrote the same answer as you! Thus, this becomes a problem of finding whatis known in game theory as the “focal point,” or “Schelling point.” You can read more about focalpoints at http://en.wikipedia.org/wiki/Focal_point_(game_theory) or in economist Thomas
Schelling’s book The Strategy Of Conflict .