HMMT 十一月 2013 · 冲刺赛 · 第 29 题
HMMT November 2013 — Guts Round — Problem 29
题目详情
英文原题
- [ 15 ] Let 4 XY Z be a right triangle with ∠ XY Z = 90 . Suppose there exists an infinite sequence ofequilateral triangles X Y T , X Y T , . . . such that X = X, Y = Y , X lies on the segment XZ for all
0 0 0 1 1 1 0 0 ii ≥ 0, Y lies on the segment Y Z for all i ≥ 0, X Y is perpendicular to Y Z for all i ≥ 0, T and Y arei i i iseparated by line XZ for all i ≥ 0, and X lies on segment Y T for i ≥ 1.
i i − 1 i − 1
Let P denote the union of the equilateral triangles. If the area of P is equal to the area of XY Z , find
.XY
Y Z
2 2 2
解析
英文解析
- [ 15 ] Let 4 XY Z be a right triangle with ∠ XY Z = 90 . Suppose there exists an infinite sequence ofequilateral triangles X Y T , X Y T , . . . such that X = X, Y = Y , X lies on the segment XZ for all
0 0 0 1 1 1 0 0 ii ≥ 0, Y lies on the segment Y Z for all i ≥ 0, X Y is perpendicular to Y Z for all i ≥ 0, T and Y arei i i iseparated by line XZ for all i ≥ 0, and X lies on segment Y T for i ≥ 1.
i i − 1 i − 1
Let P denote the union of the equilateral triangles. If the area of P is equal to the area of XY Z , find
.XY
Y Z
Answer: 1 For any region R , let [ R ] denote its area.
2 4
Let a = XY , b = Y Z , ra = X Y . Then [ P ] = (), [ XY Z ] = ($1 +
1 1 0 1 1
√ √
2 4 2
r + r + · · ·$), Y Y = ra 3, and b = ra 3(1 + r + r + · · · ) (although we can also get this by similartriangles).1
√ √
√
a 3 1 3 − 1 XY a 1 − r 2
√
Hence = ( ra + a )( ra 3), or 2 r ( r + 1) = 1 = ⇒ r = . Thus = = = 1.
4 2 2 Y Z br 3
2 2 2