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HMMT 二月 2013 · 团队赛 · 第 7 题

HMMT February 2013 — Team Round — Problem 7

专题
Contest Math / 竞赛数学
难度
L3
来源
HMMT

题目详情

英文原题

  1. [ 30 ] There are n children and n toys such that each child has a strict preference ordering on the toys.
    We want to distribute the toys: say a distribution A dominates a distribution B 6 = A if in A , eachchild receives at least as preferable of an toy as in B . Prove that if some distribution is not dominatedby any other, then at least one child gets his/her favorite toy in that distri bution.
解析

英文解析

  1. [ 30 ] There are n children and n toys such that each child has a strict preference ordering on the toys.
    We want to distribute the toys: say a distribution A dominates a distribution B 6 = A if in A , eachchild receives at least as preferable of an toy as in B . Prove that if some distribution is not dominatedby any other, then at least one child gets his/her favorite toy in that distribution.
    Answer: N/A Suppose we have a distribution A assigning each child C , i = 1 , 2 , . . . , n , toy T ,
    i i
    ′
    such that no child C gets their top preference T 6 = T . Then, pick an arbitrary child C and constructi i 1
    ′ithe sequence of children C , C , C , . . . where i = 1 and C was assigned the favorite toy T ofi i i 1 i
    1 2 3 k +1 ikthe last child C . Eventually, some C = C ; at this point, just pass the toys around this cyclei i ik k 1
    so that each of these children gets their favorite toy. Clearly the resulting distribution dominates theoriginal, so we’re done.