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HMMT 二月 2013 · 团队赛 · 第 1 题

HMMT February 2013 — Team Round — Problem 1

专题
Contest Math / 竞赛数学
难度
L3
来源
HMMT

题目详情

  1. [ 10 ] Let a and b be real numbers such that = . Find all possible values of .
    2 2 2 2
    a + b 4 a + b

英文原题

Choose a row, and subtract 1 from each entry.

解析

英文解析

  1. [ 10 ] Let a and b be real numbers such that = . Find all possible values of .
    2 2 2 2
    a + b 4 a + b
    √
    Answer: The hypothesis statement is equivalent to 3
    2 22
    a + b = 4 ab
    1 : ( a + b ) = 6 ab 2
    2 : ( a − b ) = 2 ab 2
    Multiplying equations 1 and 2,
    2 2 2 2
    ( a − b ) = 12( ab )
    √
    2 2
    | a − b | = ± 12 ab
    Since the left hand side and ab are both positive,
    √
    2 2
    | a − b | = 12 ab
    √ √ √
    2 2
    | a − b | 12 ab 12 3 = = =
    2 2 2 2
    a + b a + b 4 2
    (It is clear that such a and b exist: for example, we can take a = 1 and solve for b by way of thequadratic formula.)