HMMT 二月 2013 · 团队赛 · 第 1 题
HMMT February 2013 — Team Round — Problem 1
题目详情
- [ 10 ] Let a and b be real numbers such that = . Find all possible values of .
2 2 2 2
a + b 4 a + b
英文原题
Choose a row, and subtract 1 from each entry.
解析
英文解析
- [ 10 ] Let a and b be real numbers such that = . Find all possible values of .
2 2 2 2
a + b 4 a + b
√
Answer: The hypothesis statement is equivalent to 3
2 22
a + b = 4 ab
1 : ( a + b ) = 6 ab 2
2 : ( a − b ) = 2 ab 2
Multiplying equations 1 and 2,
2 2 2 2
( a − b ) = 12( ab )
√
2 2
| a − b | = ± 12 ab
Since the left hand side and ab are both positive,
√
2 2
| a − b | = 12 ab
√ √ √
2 2
| a − b | 12 ab 12 3 = = =
2 2 2 2
a + b a + b 4 2
(It is clear that such a and b exist: for example, we can take a = 1 and solve for b by way of thequadratic formula.)