HMMT 二月 2013 · 冲刺赛 · 第 17 题
HMMT February 2013 — Guts Round — Problem 17
题目详情
英文原题
- [ 11 ] The lines y = x , y = 2 x , and y = 3 x are the three medians of a triangle with perimeter 1. Findthe length of the longest side of the triangle.
解析
英文解析
- [ 11 ] The lines y = x , y = 2 x , and y = 3 x are the three medians of a triangle with perimeter 1. Findthe length of the longest side of the triangle.
√
√ √58
Answer: The three medians of a triangle contain its vertices, so the three vertices of
2+ 34+ 58
the triangle are ( a, a ), ( b, 2 b ) and ( c, 3 c ) for some a , b , and c . Then, the midpoint of ( a, a ) and ( b, 2 b ),
a + b a +2 bwhich is ( , ), must lie along the line y = 3 x . Therefore,
2 2
a + 2 b a + b = 3 · ,
2 2
a + 2 b = 3 a + 3 b,
− 2 a = b.
b + c 2 b +3 c
Similarly, the midpoint of ( b, 2 b ) and ( c, 3 c ), which is ( , ), must lie along the line y = x .
2 2
Therefore,
2 b + 3 c b + c = ,
2 2
2 b + 3 c = b + c,
b = − 2 c,
c = − b = a.1
From this, three points can be represented as ( a, a ), ( − 2 a, − 4 a ), and ( a, 3 a ). Using the distance 2
√ √
formula, the three side lengths of the triangle are 2 | a | , 34 | a | , and 58 | a | . Since the perimeter of the
√
1 58
√ √ √ √
triangle is 1, we find that | a | = and therefore the longest side length is .
2+ 34+ 58 2+ 34+ 58