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HMMT 二月 2013 · 代数 · 第 3 题

HMMT February 2013 — Algebra — Problem 3

专题
Contest Math / 竞赛数学
难度
L3
来源
HMMT

题目详情

英文原题

Let Sbe the set of integers of the form 2x+ 2y+ 2z, where x, y, z are pairwise distinct non-negative integers. Determine the 100th smallest element of S.

解析

英文解析

  1. Let S be the set of integers of the form 2 + 2 + 2 , where x, y, z are pairwise distinct non-negativeintegers. Determine the 100 th smallest element of S .
    Answer: 577 S is the set of positive integers with exactly three ones in its binary representation.
    ( ) ( ) ( )
    d 9 10
    The number of such integers with at most d total bits is , and noting that = 84 and = 120,
    3 3 3
    9 x y 9
    we want the 16 th smallest integer of the form 2 + 2 + 2 , where y < x < 9. Ignoring the 2 term,
    ( ) ( )
    ′
    d 6
    x y ′
    there are positive integers of the form 2 + 2 with at most d total bits. Because = 15, our
    2 2
    9 6 0
    answer is 2 + 2 + 2 = 577. (By a bit , we mean a digit in base 2.)