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HMMT 十一月 2012 · 冲刺赛 · 第 34 题

HMMT November 2012 — Guts Round — Problem 34

专题
Contest Math / 竞赛数学
难度
L3
来源
HMMT

题目详情

英文原题

  1. [ 20 ] For a positive integer n , let τ ( n ) be the number of divisors of n . Determine τ ( n ). Yourn =1
    { ⌊ ⌋}
    ( )
    | S − k |3
    score will be max 0 , 20 1 − , where k is your answer and S is the actual answer. S
解析

英文解析

  1. [ 20 ]
    Answer: 15612 Note that the number of integers between 1 and 2012 that have n as a divi-
    2012
    sor is ⌊ ⌋ . Therefore, if we sum over the possible divisors, we see that the sum is equivalent ton
    ∑ ∑ ∑
    2012 2012 2012
    2012 2012 1
    ⌊ ⌋ . This can be approximated by = 2012 ≈ 2012 ln(2012). As it turnsd =1 d =1 d =1
    d d dout, 2012 ln(2012) ≈ 15300, which is worth 18 points. Using the very rough approximation ln(2012) ≈ 7
    still gives 14 points.