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HMMT 二月 2012 · 几何 · 第 8 题

HMMT February 2012 — Geometry — Problem 8

专题
Contest Math / 竞赛数学
难度
L3
来源
HMMT

题目详情

英文原题

Hexagon ABCDEF has a circumscribed circle and an inscribed circle. If AB= 9,BC= 6,CD = 2,
andEF= 4. Find {DE, FA }.

解析

英文解析

  1. Hexagon ABCDEF has a circumscribed circle and an inscribed circle. If AB = 9, BC = 6, CD = 2,
    and EF = 4. Find { DE, F A } .
    √ √
    9+ 33 9 − 33
    Answer: { , } By Brianchon’s Theorem, AD, BE, CF concur at some point P . Also, it
    2 2
    follows from the fact that tangents from a point to a circle have equal lengths that AB + CD + EF =
    BC + DE + F A . Let DE = x , so that F A = 9 − x .
    Note that AP B ∼ EP D , BP C ∼ F P E , and CP D ∼ AP F . The second similarty gives BP/F P = 3 / 2,
    so that BP = 3 y, F P = 2 y for some y . From here, the first similarity gives DP = xy/ 3. Now, the
    √
    9 ± 33
    (9 − x ) xythird similarity gives 4 y = , so that x − 9 x + 12 = 0. It follows that x = , giving our 2
    answer.23