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HMMT 二月 2012 · 几何 · 第 2 题

HMMT February 2012 — Geometry — Problem 2

专题
Contest Math / 竞赛数学
难度
L3
来源
HMMT

题目详情

英文原题

Let ABC be a triangle with ∠A= 90◦,AB= 1, and AC= 2. Let ℓbe a line through Aperpendicular
toBC, and let the perpendicular bisectors of ABandACmeet ℓatEandF, respectively. Find the
length of segment EF.

解析

英文解析

  1. Let ABC be a triangle with ∠ A = 90 , AB = 1, and AC = 2. Let ℓ be a line through A perpendicularto BC , and let the perpendicular bisectors of AB and AC meet ℓ at E and F , respectively. Find the length of segment EF .
    √
    3 5
    Answer: Let M, N be the midpoints of AB and AC , respectively. Then we have ∠ EAB =
    √4
    √
    ∠ ACB and ∠ EAC = ∠ ABC , so AEM ∼ CBA ⇒ AE = and F AN ∼ CBA ⇒ AF = 5.5
    √4
    3 5
    Consequently, EF = AF − AE = . 4