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HMMT 二月 2012 · 代数 · 第 6 题

HMMT February 2012 — Algebra — Problem 6

专题
Contest Math / 竞赛数学
难度
L3
来源
HMMT

题目详情

英文原题

Let a0=−2,b0= 1, and for n≥0, let
an+1=an+bn+/radicalbig
a2n+b2n,
bn+1=an+bn−/radicalbig
a2n+b2n.
Find a2012.

解析

英文解析

  1. Let a = − 2, b = 1, and for n ≥ 0, let
    0 0
    √
    2 2
    a = a + b + a + b ,
    n +1 n nn n
    √
    2 2
    b = a + b − a + b .
    n +1 n nn n
    Find a .
    2012
    √
    1006 2011
    2010
    Answer: 2 2 + 2 − 2 We have a + b = 2( a + b )
    n +1 n +1 n n
    2 2 2
    a b = ( a + b ) − a − b = 2 a bn +1 n +1 n n n nn n
    Thus,
    a + b = − 2 nn nn +1
    a b = − 2
    n n
    Using Viete’s formula, a and b are the roots of the following quadratic, and, since the square
    2012 2012
    root is positive, a is the bigger root:
    2012
    2 2012 2013
    x + 2 x − 2
    Thus,
    √
    1006 2011
    2010
    a = 2 2 + 2 − 2
    2012