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HMMT 二月 2012 · 代数 · 第 2 题

HMMT February 2012 — Algebra — Problem 2

专题
Contest Math / 竞赛数学
难度
L3
来源
HMMT

题目详情

英文原题

You are given an unlimited supply of red, blue, and yellow cards to form a hand. Eac h card has a point
value and your score is the sum of the point values of those cards. The point va lues are as follows: the
value of each red card is 1, the value of each blue card is equal to twice the number of red cards, and
the value of each yellow card is equal to three times the number of blue cards. What i s the maximum
score you can get with fifteen cards?

解析

英文解析

  1. You are given an unlimited supply of red, blue, and yellow cards to form a hand. Each card has a pointvalue and your score is the sum of the point values of those cards. The point values are as follows: the value of each red card is 1, the value of each blue card is equal to twice the number of red cards, andthe value of each yellow card is equal to three times the number of blue cards. What is the maximumscore you can get with fifteen cards?
    Answer: 168 If there are B blue cards, then each red card contributes 1 + 2 B points (one for itselfand two for each blue card) and each yellow card contributes 3 B points. Thus, if B > 1, it is optimalto change all red cards to yellow cards. When B = 0, the maximum number of points is 15. When
    B = 1, the number of points is always 42. When B > 1, the number of points is 3 BY , where Y isthe number of yellow cards. Since B + Y = 15, the desired maximum occurs when B = 7 and Y = 8,
    which gives 168 points.