HMMT 十一月 2011 · THM 赛 · 第 8 题
HMMT November 2011 — THM Round — Problem 8
题目详情
英文原题
- [ 5 ] Points D, E, F lie on circle O such that the line tangent to O at D intersects ray EF at P . Given
°
that P D = 4, P F = 2, and ∠ F P D = 60 , determine the area of circle O .
解析
英文解析
- [ 5 ] Points D, E, F lie on circle O such that the line tangent to O at D intersects ray EF at P . Given
°
that P D = 4, P F = 2, and ∠ F P D = 60 , determine the area of circle O .
Theme Round
Answer: 12 π By the power of a point on P , we get that
16 = P D = ( P F )( P E ) = 2( P E ) ⇒ P E = 8 .2
°
However, since P E = 2 P D and ∠ F P D = 60 , we notice that P DE is a 30 − 60 − 90 triangle, so
√
DE = 4 3 and we have ED ⊥ DP . It follows that DE is a diameter of the circle, since tangentsthe tangent at D must be perpendicular to the radius containing D . Hence, the area of the circle is
( DE ) π = 12 π .21
D 4 P2
√2
2 3F
E6