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HMMT 十一月 2011 · THM 赛 · 第 8 题

HMMT November 2011 — THM Round — Problem 8

专题
Contest Math / 竞赛数学
难度
L3
来源
HMMT

题目详情

英文原题

  1. [ 5 ] Points D, E, F lie on circle O such that the line tangent to O at D intersects ray EF at P . Given
    °
    that P D = 4, P F = 2, and ∠ F P D = 60 , determine the area of circle O .
解析

英文解析

  1. [ 5 ] Points D, E, F lie on circle O such that the line tangent to O at D intersects ray EF at P . Given
    °
    that P D = 4, P F = 2, and ∠ F P D = 60 , determine the area of circle O .
    Theme Round
    Answer: 12 π By the power of a point on P , we get that
    16 = P D = ( P F )( P E ) = 2( P E ) ⇒ P E = 8 .2
    °
    However, since P E = 2 P D and ∠ F P D = 60 , we notice that P DE is a 30 − 60 − 90 triangle, so
    √
    DE = 4 3 and we have ED ⊥ DP . It follows that DE is a diameter of the circle, since tangentsthe tangent at D must be perpendicular to the radius containing D . Hence, the area of the circle is
    ( DE ) π = 12 π .21
    D 4 P2
    √2
    2 3F
    E6