HMMT 十一月 2011 · THM 赛 · 第 6 题
HMMT November 2011 — THM Round — Problem 6
题目详情
英文原题
- [ 3 ] Let ABC be an equilateral triangle with AB = 3. Circle ω with diameter 1 is drawn inside the triangle such that it is tangent to sides AB and AC . Let P be a point on ω and Q be a point onsegment BC . Find the minimum possible length of the segment P Q .
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解析
英文解析
- [ 3 ] Let ABC be an equilateral triangle with AB = 3. Circle ω with diameter 1 is drawn inside the triangle such that it is tangent to sides AB and AC . Let P be a point on ω and Q be a point onsegment BC . Find the minimum possible length of the segment P Q .
Theme Round
√
3 3 − 3
Answer: Let P , Q , be the points which minimize the distance. We see that we want both
√2
3 3
to lie on the altitude from A to BC . Hence, Q is the foot of the altitude from A to BC and AQ = .
Let O , which must also lie on this line, be the center of ω , and let D be the point of tangency between 2
1 1
°
ω and AC . Then, since OD = , we have AO = 2 OD = 1 because ∠ OAD = 30 , and OP = .
2 2
Consequently,
√
3 3 − 3
P Q = AQ − AO − OP = .
A2
B Q CPOD
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