HMMT 十一月 2011 · 冲刺赛 · 第 32 题
HMMT November 2011 — Guts Round — Problem 32
题目详情
英文原题
[17] Find all real numbers xsatisfying x9+9 8x6+27 64x3−x+219 512= 0.
解析
英文解析
- [ 17 ] Find all real numbers x satisfying
9 27 219
9 6 3
x + x + x − x + = 0 .
8 64 512
√
1 − 1 ± 13
Answer: , Note that we can re-write the given equation as
2 4
√
3 3
x − = x + .33
8 8
Furthermore, the functions of x on either side, we see, are inverses of each other and increasing. Let
√
3 3 − 1
f ( x ) = x − . Suppose that f ( x ) = y = f ( x ). Then, f ( y ) = x . However, if x < y , we havef ( x ) > f ( y ), contradicting the fact that f is increasing, and similarly, if y < x , we have f ( x ) < f ( y ),8 − 1
again a contradiction. Therefore, if f ( x ) = f ( x ) and both are increasing functions in x , we requiref ( x ) = x . This gives the cubic
( ) ( )
3 1 1 3
3 2
x − x + = 0 → x − x + x − = 0 ,
8 2 2 4
√
1 − 1 ± 13
giving x = , .
2 4