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HMMT 十一月 2011 · 冲刺赛 · 第 25 题

HMMT November 2011 — Guts Round — Problem 25

专题
Contest Math / 竞赛数学
难度
L3
来源
HMMT

题目详情

英文原题

[12] LetXY Z be an equilateral triangle, and let K, L, M be points on sides XY, Y Z, ZX , respectively, such that XK/KY =B,Y L/LZ = 1/C, and ZM/MX = 1. Determine the ratio of the area of triangle KLM to the area of triangle XY Z .

解析

英文解析

  1. [ 12 ] Let XY Z be an equilateral triangle, and let K, L, M be points on sides XY, Y Z, ZX , respectively,
    such that XK/KY = B , Y L/LZ = 1 /C , and ZM/M X = 1. Determine the ratio of the area oftriangle KLM to the area of triangle XY Z .
    Answer: First, we note that 1
    [ KLM ] = [ XY Z ] − [ XKM ] − [ Y LK ] − [ ZM L ] .5
    Then, note that
    XK XM B 1
    [ XKM ] = · · [ XY Z ] = · · [ XY Z ]
    XY XZ B + 1 2
    Y L Y K 1 1
    [ Y LK ] = · · [ XY Z ] = · · [ XY Z ]
    Y Z Y X C + 1 B + 1
    ZM ZL 1 1
    [ ZM L ] = · · [ XY Z ] = · · [ XY Z ]
    ZX ZY 2 C + 1
    Consequently,
    [ KLM ]
    A =
    [ XY Z ]
    B 1 1 1 C 1 = 1 − · − · − ·
    B + 1 2 C + 1 B + 1 C + 1 2
    B + C
    ( B + 1)( C + 1)(2)=
    If we solve our system of equations for A, B, C , we get that A = .1
    Y5
    K151
    L3
    3254
    X Z
    1 1
    2 2M