HMMT 二月 2011 · TEAM2 赛 · 第 11 题
HMMT February 2011 — TEAM2 Round — Problem 11
题目详情
- [ 10 ] Let H be the intersection of the three altitudes of triangle ABC . (This point is usually called the orthocenter). Prove that ∠ DAH = ∠ M AO .
解析
- [ 10 ] Let H be the intersection of the three altitudes of triangle ABC . (This point is usually called the orthocenter). Prove that ∠ DAH = ∠ M AO . Solution: Note that since both AH and OX are perpendicular to BC , it follows that AH ‖ OX , so ∠ DAH = ∠ DXO = ∠ AXO = ∠ M AO , as desired.