HMMT 二月 2011 · 冲刺赛 · 第 28 题
HMMT February 2011 — Guts Round — Problem 28
题目详情
英文原题
- [ 16 ] Let ABC be a triangle, and let points P and Q lie on BC such that P is closer to B than Q is.
Suppose that the radii of the incircles of triangles ABP , AP Q , and AQC are all equal to 1, and that the radii of the corresponding excircles opposite A are 3, 6, and 5, respectively. If the radius of theincircle of triangle ABC is , find the radius of the excircle of triangle ABC opposite A .3
14 HARVARD-MIT MATHEMATICS TOURNAMENT, 12 FEBRUARY 2011 — GUTS ROUNDth
解析
英文解析
- [ 16 ] Let ABC be a triangle, and let points P and Q lie on BC such that P is closer to B than Q is.
Suppose that the radii of the incircles of triangles ABP , AP Q , and AQC are all equal to 1, and that the radii of the corresponding excircles opposite A are 3, 6, and 5, respectively. If the radius of theincircle of triangle ABC is , find the radius of the excircle of triangle ABC opposite A .3
Answer: 1352
Let t denote the radius of the excircle of triangle 4 ABC .
Lemma: Let 4 ABC be a triangle, and let r and r be the inradius and exradius opposite A . Thenr B CA = tan tan .
r 2 2
Guts Round a
Proof. Let I and J denote the incenter and the excenter with respect to A . Let D and E be the footof the perpendicular from I and J to BC , respectively. Thenr = ID = BI sin b
°2
180 − B Br = JE = BJ sin = BJ cos
2 2A
BI = BJ tan ∠ AJB = BY tan .C
The last equation followed from 2
°
180 − B A C
°
∠ AJB = 180 − ∠ ABJ − ∠ JAB = − = .
2 2 2
Hencesin br BI B C = · = tan · tan .2
r BJ 2 2Bcos
2A
∠ AP Q ∠ AQP ∠ AQC
∠ AP B
Noting tan tan = tan tan = 1 and applying the lemma to 4 ABC , 4 ABP ,
2 2 2 2
4 AP Q , and 4 AQC give
3 / 2 ∠ ABC ∠ ACB = tan · tant 2 2
( ) ( ) ( )
∠ ABC ∠ AP B ∠ AP Q ∠ AQP ∠ AQC ∠ ACB = tan · tan · tan · tan · tan · tan
2 2 2 2 2 2
1 1 1 = · ·
3 6 5
Therefore, t = 135.