HMMT 二月 2011 · 冲刺赛 · 第 10 题
HMMT February 2011 — Guts Round — Problem 10
题目详情
英文原题
- [ 6 ] In how many ways can one fill a 4 × 4 grid with a 0 or 1 in each square such that the sum of theentries in each row, column, and long diagonal is even?
解析
英文解析
- [ 6 ] In how many ways can one fill a 4 × 4 grid with a 0 or 1 in each square such that the sum of theentries in each row, column, and long diagonal is even?
Answer: 256
First we name the elements of the square as follows:
a a a a
11 12 13 14
a a a a
21 22 23 24
a a a a
31 32 33 34
a a a a
41 42 43 44
We claim that for any given values of a , a , a , a , a , a , a , and a (the + signs in the diagram
11 12 13 21 22 23 32 33
below), there is a unique way to assign values to the rest of the entries such that all necessary sumsare even.
-
-
- a + + + a 14
a + + a 24
31 34
a a a a
41 42 43 44
Guts Round
Taking additions mod 2, we have a = a + a + a
14 11 12 13
a = a + a + a
24 21 22 23
a = a + a + a
44 11 22 33
a = a + a + a
42 12 22 32
a = a + a + a
43 13 23 33
Since the 4 th column, the 4 th row, and the 1 st column must have entries that sum to 0, we have a = a + a + a = a + a + a + a + a
34 14 24 44 12 13 21 23 33
a = a + a + a = a + a + a + a + a
41 42 43 44 11 12 13 23 32
a = a + a + a = a + a + a + a + a
31 11 21 41 12 13 21 23 32
It is easy to check that the sum of entries in every row, column, and the main diagonal is even. Sincethere are 2 = 256 ways to assign the values to the initial 8 entries, there are exactly 256 ways to fill 8
the board.
- a + + + a 14
-