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HMMT 二月 2011 · 冲刺赛 · 第 10 题

HMMT February 2011 — Guts Round — Problem 10

专题
Contest Math / 竞赛数学
难度
L3
来源
HMMT

题目详情

英文原题

  1. [ 6 ] In how many ways can one fill a 4 × 4 grid with a 0 or 1 in each square such that the sum of theentries in each row, column, and long diagonal is even?
解析

英文解析

  1. [ 6 ] In how many ways can one fill a 4 × 4 grid with a 0 or 1 in each square such that the sum of theentries in each row, column, and long diagonal is even?
    Answer: 256
    First we name the elements of the square as follows:
    a a a a
    11 12 13 14
    a a a a
    21 22 23 24
    a a a a
    31 32 33 34
    a a a a
    41 42 43 44
    We claim that for any given values of a , a , a , a , a , a , a , and a (the + signs in the diagram
    11 12 13 21 22 23 32 33
    below), there is a unique way to assign values to the rest of the entries such that all necessary sumsare even.
      • a + + + a 14
        a + + a 24
        31 34
        a a a a
        41 42 43 44
        Guts Round
        Taking additions mod 2, we have a = a + a + a
        14 11 12 13
        a = a + a + a
        24 21 22 23
        a = a + a + a
        44 11 22 33
        a = a + a + a
        42 12 22 32
        a = a + a + a
        43 13 23 33
        Since the 4 th column, the 4 th row, and the 1 st column must have entries that sum to 0, we have a = a + a + a = a + a + a + a + a
        34 14 24 44 12 13 21 23 33
        a = a + a + a = a + a + a + a + a
        41 42 43 44 11 12 13 23 32
        a = a + a + a = a + a + a + a + a
        31 11 21 41 12 13 21 23 32
        It is easy to check that the sum of entries in every row, column, and the main diagonal is even. Sincethere are 2 = 256 ways to assign the values to the initial 8 entries, there are exactly 256 ways to fill 8
        the board.