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HMMT 十一月 2010 · 团队赛 · 第 4 题

HMMT November 2010 — Team Round — Problem 4

专题
Contest Math / 竞赛数学
难度
L3
来源
HMMT

题目详情

英文原题

  1. [ 6 ] In terms of k , for k > 0, how likely is it that after k minutes Sherry is at the vertex opposite the vertex where she started?
    Circles in Circles
解析

英文解析

  1. [ 6 ] In terms of k , for k > 0, how likely is it that after k minutes Sherry is at the vertex opposite the vertex where she started?
    1 1
    Answer: + Take p ( n ) from the last problem. By examining the last move of Sherry, thek
    6 3( − 2)
    probability that she ends up on the original vertex is equal to the probability that she ends up on the
    1 − p ( n )
    top vertex, and both are equal to for n ≥ 1.
    From the last problem,2
    p ( n )
    p ( n + 1) = 1 −
    ( )2
    2 1 2
    p ( n + 1) − = − p ( n ) −
    3 2 3
    ( )
    2 1 2 2 1 nand so p ( n ) − is a geometric series with ratio − . Since p (0) = 0, we get p ( n ) − = − − , or
    3 2 3 3 2
    ( )
    2 2 1 nthat p ( n ) = − − .
    3 3 2
    Now, for k ≥ 1, we have that the probability of ending up on the vertex opposite Sherry’s initial vertex
    ( )
    ( ) ( )
    k k
    1 − p ( k )
    1 1 2 2 1 1 1 1 1 1
    after k minutes is = − − − = + − = + .
    2 2 2 3 3 2 6 3 2 6 3( − 2)k
    Circles in Circles