HMMT 十一月 2010 · 团队赛 · 第 4 题
HMMT November 2010 — Team Round — Problem 4
题目详情
英文原题
- [ 6 ] In terms of k , for k > 0, how likely is it that after k minutes Sherry is at the vertex opposite the vertex where she started?
Circles in Circles
解析
英文解析
- [ 6 ] In terms of k , for k > 0, how likely is it that after k minutes Sherry is at the vertex opposite the vertex where she started?
1 1
Answer: + Take p ( n ) from the last problem. By examining the last move of Sherry, thek
6 3( − 2)
probability that she ends up on the original vertex is equal to the probability that she ends up on the
1 − p ( n )
top vertex, and both are equal to for n ≥ 1.
From the last problem,2
p ( n )
p ( n + 1) = 1 −
( )2
2 1 2
p ( n + 1) − = − p ( n ) −
3 2 3
( )
2 1 2 2 1 nand so p ( n ) − is a geometric series with ratio − . Since p (0) = 0, we get p ( n ) − = − − , or
3 2 3 3 2
( )
2 2 1 nthat p ( n ) = − − .
3 3 2
Now, for k ≥ 1, we have that the probability of ending up on the vertex opposite Sherry’s initial vertex
( )
( ) ( )
k k
1 − p ( k )
1 1 2 2 1 1 1 1 1 1
after k minutes is = − − − = + − = + .
2 2 2 3 3 2 6 3 2 6 3( − 2)k
Circles in Circles