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HMMT 十一月 2010 · GEN2 赛 · 第 7 题

HMMT November 2010 — GEN2 Round — Problem 7

专题
Contest Math / 竞赛数学
难度
L3
来源
HMMT

题目详情

英文原题

  1. [ 4 ] George has two coins, one of which is fair and the other of which always comes up heads. Jacobtakes one of them at random and flips it twice. Given that it came up heads both times, what is the probability that it is the coin that always comes up heads? 2
解析

英文解析

  1. [ 4 ] George has two coins, one of which is fair and the other of which always comes up heads. Jacobtakes one of them at random and flips it twice. Given that it came up heads both times, what is the probability that it is the coin that always comes up heads?
    P ( A ∩ B )
    Answer: In general, P ( A | B ) = , where P ( A | B ) is the probability of A given B and 4
    5 P ( B )
    P ( A ∩ B ) is the probability of A and B (See http://en.wikipedia.org/wiki/Conditional probabilityfor more information). If A is the event of selecting the “double-headed” coin and B is the event of
    1 1
    Jacob flipping two heads, then P ( A ∩ B ) = ( )(1), since there is a chance of picking the double-
    2 2
    headed coin and Jacob will always flip two heads when he has it. By conditional probability, P ( B ) =
    1 / 2
    1 1 1 5 4
    ( )(1) + ( )( ) = , so P ( A | B ) = = .
    2 2 4 8 5 / 8 5 2