HMMT 十一月 2010 · GEN1 赛 · 第 10 题
HMMT November 2010 — GEN1 Round — Problem 10
题目详情
英文原题
- [ 8 ] You are given two diameters AB and CD of circle Ω with radius 1. A circle is drawn in one of thesmaller sectors formed such that it is tangent to AB at E , tangent to CD at F , and tangent to Ω at
P . Lines P E and P F intersect Ω again at X and Y . What is the length of XY , given that AC = ?2 3
解析
英文解析
- [ 8 ] You are given two diameters AB and CD of circle Ω with radius 1. A circle is drawn in one of thesmaller sectors formed such that it is tangent to AB at E , tangent to CD at F , and tangent to Ω at
P . Lines P E and P F intersect Ω again at X and Y . What is the length of XY , given that AC = ?2
√3
4 2
Answer: Let O denote the center of circle Ω. We first prove that OX ⊥ AB and OY ⊥ CD .
Consider the homothety about P which maps the smaller circle to Ω. This homothety takes E to X3
and also takes AB to the line tangent to circle Ω parallel to AB . Therefore, X is the midpoint of thearc AB , and so OX ⊥ AB . Similarly, OY ⊥ CD .
√
θ θ 1 θ 1
Let θ = ∠ AOC . By the Law of Sines, we have AC = 2 sin . Thus, sin = , and cos = 1 − ( ) =2
2 2 3 2 3
√
2 2
. Therefore,
∠ XOY3
XY = 2 sin
( )2
°θ = 2 sin 90 −
θ2 = 2 cos
√2
4 2 = .
General Test 3