HMMT 二月 2010 · 冲刺赛 · 第 9 题
HMMT February 2010 — Guts Round — Problem 9
题目详情
- [ 6 ] Indecisive Andy starts out at the midpoint of the 1-unit-long segment HT . He flips 2010 coins. On each flip, if the coin is heads, he moves halfway towards endpoint H , and if the coin is tails, he moves halfway towards endpoint T . After his 2010 moves, what is the expected distance between Andy and the midpoint of HT ? . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . th 13 ANNUAL HARVARD-MIT MATHEMATICS TOURNAMENT, 20 FEBRUARY 2010 — GUTS ROUND
解析
- [ 6 ] Indecisive Andy starts out at the midpoint of the 1-unit-long segment HT . He flips 2010 coins. On each flip, if the coin is heads, he moves halfway towards endpoint H , and if the coin is tails, he moves halfway towards endpoint T . After his 2010 moves, what is the expected distance between Andy and the midpoint of HT ? 1 Answer: Let Andy’s position be x units from the H end after 2009 flips. If Any moves towards 4 x 1 − x the H end, he ends up at , a distance of from the midpoint. If Andy moves towards the T end, 2 2 1+ x x he ends up at , a distance of from the midpoint. His expected distance from the midpoint is then 2 2 1 − x x
1 2 2 = . 2 4 1 Since this does not depend on x , is the answer. 4 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . th 13 ANNUAL HARVARD-MIT MATHEMATICS TOURNAMENT, 20 FEBRUARY 2010 — GUTS ROUND