HMMT 二月 2010 · 冲刺赛 · 第 26 题
HMMT February 2010 — Guts Round — Problem 26
题目详情
英文原题
- [ 15 ] Express the following in closed form, as a function of x :
2 2 2 2
2 2 2 2010 2 2009 2 2
sin ( x )+sin (2 x ) cos ( x )+sin (4 x ) cos (2 x ) cos ( x )+ · · · +sin (2 x ) cos (2 x ) · · · cos (2 x ) cos ( x ) .
解析
英文解析
- [ 15 ] Express the following in closed form, as a function of x :
2 2 2 2
2 2 2 2010 2 2009 2 2
sin ( x )+sin (2 x ) cos ( x )+sin (4 x ) cos (2 x ) cos ( x )+ · · · +sin (2 x ) cos (2 x ) · · · cos (2 x ) cos ( x ) .
2 2011
sin (2 x )
Answer: 1 − Note that
20112
4 sin ( x )
2 2 2 2 2010 2 2009 2 2
sin ( x ) + sin (2 x ) cos ( x ) + · · · + sin (2 x ) cos (2 x ) · · · cos (2 x ) cos ( x )
2 2 2 2 2010 2 2009 2 = (1 − cos ( x )) + (1 − cos (2 x )) cos ( x ) + · · · + (1 − cos (2 x )) cos (2 x ) · · · cos ( x ) ,
2 2 2 2 2010 2 2 2 2010
which telescopes to 1 − cos ( x ) cos (2 x ) cos (4 x ) · · · cos (2 x ). To evaluate cos ( x ) cos (2 x ) · · · cos (2 x ),
multiply and divide by sin ( x ). We then get 2
2 2 2 20102
sin ( x ) cos ( x ) cos (2 x ) · · · cos (2 x )
1 − .
sin ( x )2
sin (2 y )2
Using the double-angle formula for sin, we get that sin ( y ) cos ( y ) = . Applying this 2011 times 22
makes the above expression 4
20112
sin (2 x )
1 − ,
20112
4 sin ( x )
which is in closed form.