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HMMT 二月 2010 · 冲刺赛 · 第 12 题

HMMT February 2010 — Guts Round — Problem 12

专题
Contest Math / 竞赛数学
难度
L3
来源
HMMT

题目详情

  1. [ 7 ] How many different collections of 9 letters are there? A letter can appear multiple times in acollection. Two collections are equal if each letter appears the same number of times in both collections.
    13 ANNUAL HARVARD-MIT MATHEMATICS TOURNAMENT, 20 FEBRUARY 2010 — GUTS ROUNDth

英文原题

[ 7 ] How many different collections of 9 letters are there? A letter can appear multiple times in a
collection. Two collections are equal if each letter appears the same number of times in both collections.
. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .
13 th ANNUAL HARVARD-MIT MATHEMATICS TOURNAMENT, 20 FEBRUARY 2010 — GUTS ROUND

解析

英文解析

  1. [ 7 ] How many different collections of 9 letters are there? A letter can appear multiple times in acollection. Two collections are equal if each letter appears the same number of times in both collections.
    ( )
    Answer: We put these collections in bijections with binary strings of length 34 containing 934
    zeroes and 25 ones. Take any such string - the 9 zeroes will correspond to the 9 letters in the collection.9
    If there are n ones before a zero, then that zero corresponds to the ( n + 1)st letter of the alphabet.
    This scheme is an injective map from the binary strings to the collections, and it has an inverse, so the
    ( )
    number of collections is .34
    13 ANNUAL HARVARD-MIT MATHEMATICS TOURNAMENT, 20 FEBRUARY 2010 — GUTS ROUNDth