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HMMT 二月 2010 · GEN1 赛 · 第 5 题

HMMT February 2010 — GEN1 Round — Problem 5

专题
Contest Math / 竞赛数学
难度
L3
来源
HMMT

题目详情

英文原题

  1. [ 4 ] Manya has a stack of 85 = 1 + 4 + 16 + 64 blocks comprised of 4 layers (the k th layer from the topk − 1
    has 4 blocks; see the diagram below). Each block rests on 4 smaller blocks, each with dimensionshalf those of the larger block. Laura removes blocks one at a time from this stack, removing only blocksthat currently have no blocks on top of them. Find the number of ways Laura can remove precisely 5
    blocks from Manya’s stack (the order in which they are removed matters).
解析

英文解析

  1. [ 4 ] Manya has a stack of 85 = 1 + 4 + 16 + 64 blocks comprised of 4 layers (the k th layer from the topk − 1
    has 4 blocks; see the diagram below). Each block rests on 4 smaller blocks, each with dimensionshalf those of the larger block. Laura removes blocks one at a time from this stack, removing only blocksthat currently have no blocks on top of them. Find the number of ways Laura can remove precisely 5
    blocks from Manya’s stack (the order in which they are removed matters).
    General Test, Part 1
    Answer: 3384 Each time Laura removes a block, 4 additional blocks are exposed, increasing the total number of exposed blocks by 3. She removes 5 blocks, for a total of 1 · 4 · 7 · 10 · 13 ways. However,
    the stack originally only has 4 layers, so we must subtract the cases where removing a block on thebottom layer does not expose any new blocks. There are 1 · 4 · 4 · 4 · 4 = 256 of these (the last factor of
    4 is from the 4 blocks that we counted as being exposed, but were not actually). So our final answeris 1 · 4 · 7 · 10 · 13 − 1 · 4 · 4 · 4 · 4 = 3384.