HMMT 二月 2010 · CALC 赛 · 第 5 题
HMMT February 2010 — CALC Round — Problem 5
题目详情
英文原题
- [ 4 ] Let the functions f ( α, x ) and g ( α ) be defined as
( )
∣
4 xα
∣
d f
∣2
f ( α, x ) = g ( α ) =
∣
x − 1 dx 4
x =2
Then g ( α ) is a polynomial in α . Find the leading coefficient of g ( α ).
3 2
解析
英文解析
- [ 4 ] Let the functions f ( α, x ) and g ( α ) be defined as
( )
∣
4 xα
∣
d f
∣2
f ( α, x ) = g ( α ) =
∣
x − 1 dx 4
x =2
Then g ( α ) is a polynomial in α . Find the leading coefficient of g ( α ).
( )
1 xα
Answer: Write the first equation as ( x − 1) f = . For now, treat α as a constant. From this
16 2
equation, repeatedly applying derivative with respect to x gives
( ) ( )
α − 1
α x
′
( x − 1) f + f =
2 2
( )
( ) ( )
α − 2
α α − 1 x
′′ ′
( x − 1) f + 2 f =
2 2 2
( ) ( )
( ) ( )
α − 3
α α − 1 α − 2 x