HMMT 二月 2010 · 代数 · 第 2 题
HMMT February 2010 — Algebra — Problem 2
题目详情
英文原题
- [ 3 ] The rank of a rational number q is the unique k for which q = + · · · + , where each a is theia a
1 k
1 1 1
smallest positive integer such that q ≥ + · · · + . Let q be the largest rational number less thana a 4
1 i
1 1 1
with rank 3, and suppose the expression for q is + + . Find the ordered triple ( a , a , a ).
1 2 3
a a a
1 2 3
解析
英文解析
- [ 3 ] The rank of a rational number q is the unique k for which q = + · · · + , where each a is theia a
1 k
1 1 1
smallest positive integer such that q ≥ + · · · + . Let q be the largest rational number less thana a 4
1 i
1 1 1
with rank 3, and suppose the expression for q is + + . Find the ordered triple ( a , a , a ).
1 2 3
a a a
1 2 3
Answer: (5 , 21 , 421) Suppose that A and B were rational numbers of rank 3 less than , and 1
1 1 1 1 1 14
let a , a , a , b , b , b be positive integers so that A = + + and B = + + are the
1 2 3 1 2 3
a a a b b b
1 2 3 1 2 3
1 1
expressions for A and B as stated in the problem. If b < a then A < ≤ < B . In other words,
1 1
a − 1 b
1 1
of all the rationals less than with rank 3, those that have a = 5 are greater than those that have 1
a = 6 , 7 , 8 , . . . Therefore we can “build” q greedily, adding the largest unit fraction that keeps q less 41
than :11
1 14
is the largest unit fraction less than , hence a = 5;
5 41
1 1 1
is the largest unit fraction less than − , hence a = 21;
21 4 52
1 1 1 1
is the largest unit fraction less than − − , hence a = 421.
421 4 5 213