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HMMT 二月 2010 · 代数 · 第 2 题

HMMT February 2010 — Algebra — Problem 2

专题
Contest Math / 竞赛数学
难度
L3
来源
HMMT

题目详情

英文原题

  1. [ 3 ] The rank of a rational number q is the unique k for which q = + · · · + , where each a is theia a
    1 k
    1 1 1
    smallest positive integer such that q ≥ + · · · + . Let q be the largest rational number less thana a 4
    1 i
    1 1 1
    with rank 3, and suppose the expression for q is + + . Find the ordered triple ( a , a , a ).
    1 2 3
    a a a
    1 2 3
解析

英文解析

  1. [ 3 ] The rank of a rational number q is the unique k for which q = + · · · + , where each a is theia a
    1 k
    1 1 1
    smallest positive integer such that q ≥ + · · · + . Let q be the largest rational number less thana a 4
    1 i
    1 1 1
    with rank 3, and suppose the expression for q is + + . Find the ordered triple ( a , a , a ).
    1 2 3
    a a a
    1 2 3
    Answer: (5 , 21 , 421) Suppose that A and B were rational numbers of rank 3 less than , and 1
    1 1 1 1 1 14
    let a , a , a , b , b , b be positive integers so that A = + + and B = + + are the
    1 2 3 1 2 3
    a a a b b b
    1 2 3 1 2 3
    1 1
    expressions for A and B as stated in the problem. If b < a then A < ≤ < B . In other words,
    1 1
    a − 1 b
    1 1
    of all the rationals less than with rank 3, those that have a = 5 are greater than those that have 1
    a = 6 , 7 , 8 , . . . Therefore we can “build” q greedily, adding the largest unit fraction that keeps q less 41
    than :11
    1 14
    is the largest unit fraction less than , hence a = 5;
    5 41
    1 1 1
    is the largest unit fraction less than − , hence a = 21;
    21 4 52
    1 1 1 1
    is the largest unit fraction less than − − , hence a = 421.
    421 4 5 213