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HMMT 十一月 2009 · 冲刺赛 · 第 27 题

HMMT November 2009 — Guts Round — Problem 27

专题
Contest Math / 竞赛数学
难度
L3
来源
HMMT

题目详情

  1. [ 14 ] ABCD is a regular tetrahedron of volume 1. Maria glues regular tetrahedra A BCD , AB CD ,
    ′ ′ ′ ′ ′ ′
    ABC D , and ABCD to the faces of ABCD . What is the volume of the tetrahedron A B C D ?
    2 ANNUAL HARVARD-MIT NOVEMBER TOURNAMENT, 7 NOVEMBER 2009 — GUTS ROUNDnd

英文原题

[ 14 ] ABCD is a regular tetrahedron of volume 1. Maria glues regular tetrahedra A ′ BCD , AB ′ CD ,
ABC ′ D , and ABCD ′ to the faces of ABCD . What is the volume of the tetrahedron A ′ B ′ C ′ D ′ ?
. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .
2 nd ANNUAL HARVARD-MIT NOVEMBER TOURNAMENT, 7 NOVEMBER 2009 — GUTS ROUND

解析

英文解析

  1. [ 14 ] ABCD is a regular tetrahedron of volume 1. Maria glues regular tetrahedra A BCD , AB CD ,
    ′ ′ ′ ′ ′ ′
    ABC D , and ABCD to the faces of ABCD . What is the volume of the tetrahedron A B C D ?
    Answer: Consider the tetrahedron with vertices at W = (1 , 0 , 0), X = (0 , 1 , 0), Y = (0 , 0 , 1),125
    1 1 127
    and Z = (1 , 1 , 1). This tetrahedron is similar to ABCD . It has center O = ( , , ). We can
    2 2 2
    ′ ′ ′ ′ ′ ′ ′ ′ ′
    construct a tetrahedron W X Y Z in the same way that A B C D was constructed by letting W
    ′ 1 1 1 ′
    be the reflection of W across XY Z and so forth. Then we see that Z = ( − , − , − ), so OZ has
    3 3 3
    √ √ 5
    5 1 5
    ′ ′ ′ ′
    length 3, whereas OZ has length 3. We thus see that W X Y Z has a side length = that 6
    6 2 31
    ′ ′ ′ ′2
    of W XY Z , so by similarity the same is true of A B C D and ABCD . In particular, the volume of
    ( )
    5 1253
    ′ ′ ′ ′
    A B C D is that of ABCD , so it is .
    3 27
    2 ANNUAL HARVARD-MIT NOVEMBER TOURNAMENT, 7 NOVEMBER 2009 — GUTS ROUNDnd