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HMMT 十一月 2009 · GEN1 赛 · 第 7 题

HMMT November 2009 — GEN1 Round — Problem 7

专题
Contest Math / 竞赛数学
难度
L3
来源
HMMT

题目详情

英文原题

  1. [ 6 ] There are 15 stones placed in a line. In how many ways can you mark 5 of these stones so that there are an odd number of stones between any two of the stones you marked?
解析

英文解析

  1. [ 6 ] There are 15 stones placed in a line. In how many ways can you mark 5 of these stones so that there are an odd number of stones between any two of the stones you marked?
    Answer: 77 Number the stones 1 through 15 in order. We note that the condition is equivalent
    ( )
    to stipulating that the stones have either all odd numbers or all even numbers. There are ways to 8
    ( )5
    choose 5 odd-numbered stones, and ways to choose all even-numbered stones, so the total number 7
    ( ) ( ) ( )5
    8 7 nof ways to pick the stones is + = 77. ( is the number of ways to choose k out of n items. It
    5 5 kn !
    equals ).
    k !( n − k )!