HMMT 二月 2009 · 冲刺赛 · 第 21 题
HMMT February 2009 — Guts Round — Problem 21
题目详情
- [ 10 ] Simplify
2 cos (ln(2009) i ) + i sin(ln(4036081) i ) .2
12 HARVARD-MIT MATHEMATICS TOURNAMENT, 21 FEBRUARY 2009 — GUTS ROUNDth
英文原题
[ 10 ] Simplify
2 cos 2 (ln(2009) i ) + i sin(ln(4036081) i ) .
. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .
12 th HARVARD-MIT MATHEMATICS TOURNAMENT, 21 FEBRUARY 2009 — GUTS ROUND
解析
英文解析
- [ 10 ] Simplify
2 cos (ln(2009) i ) + i sin(ln(4036081) i ) .2
4036082
Answer: Solution: We have
4036081
2 cos (ln(2009) i ) + i sin(ln(4036081) i ) = 1 + cos(2 ln(2009) i ) + i sin(ln(4036081) i )2 = 1 + cos(ln(4036081) i ) + i sin(ln(4036081) i )
i ln(4036081)2 = 1 + e = 1 +1
4036081
4036082
4036081=
as desired.
12 HARVARD-MIT MATHEMATICS TOURNAMENT, 21 FEBRUARY 2009 — GUTS ROUNDth