HMMT 二月 2009 · CALC 赛 · 第 8 题
HMMT February 2009 — CALC Round — Problem 8
题目详情
英文原题
- [ 7 ] Compute
√
∫
3 ( )
2 2 x +12
2 x +1 2 xx + ln x dx.
21
解析
英文解析
- [ 7 ] Compute
√
∫
3 ( )
2 2 x +12
2 x +1 2 xx + ln x dx.
Answer: 131
ln( x )
Solution: Using the fact that x = e , we evaluate the integral as follows:
∫ ∫
( )
2 2 x +1 2 22
2 x +1 2 x 2 x +1 2 x +1 2
x + ln x dx = x + x ln( x ) dx
∫
ln( x )(2 x +1) 22 = e (1 + ln( x )) dx
∫
2 2
x ln( x ) 2 = xe (1 + ln( x )) dx
2 2 2
Noticing that the derivative of x ln( x ) is 2 x (1 + ln( x )), it follows that the integral evaluates to
1 2 2 1 2
x ln( x ) 2 xe = x .
2 2
√
Evaluating this from 1 to 3 we obtain the answer. 2