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HMMT 二月 2009 · CALC 赛 · 第 8 题

HMMT February 2009 — CALC Round — Problem 8

专题
Contest Math / 竞赛数学
难度
L3
来源
HMMT

题目详情

英文原题

  1. [ 7 ] Compute
    √
    ∫
    3 ( )
    2 2 x +12
    2 x +1 2 xx + ln x dx.
    21
解析

英文解析

  1. [ 7 ] Compute
    √
    ∫
    3 ( )
    2 2 x +12
    2 x +1 2 xx + ln x dx.
    Answer: 131
    ln( x )
    Solution: Using the fact that x = e , we evaluate the integral as follows:
    ∫ ∫
    ( )
    2 2 x +1 2 22
    2 x +1 2 x 2 x +1 2 x +1 2
    x + ln x dx = x + x ln( x ) dx
    ∫
    ln( x )(2 x +1) 22 = e (1 + ln( x )) dx
    ∫
    2 2
    x ln( x ) 2 = xe (1 + ln( x )) dx
    2 2 2
    Noticing that the derivative of x ln( x ) is 2 x (1 + ln( x )), it follows that the integral evaluates to
    1 2 2 1 2
    x ln( x ) 2 xe = x .
    2 2
    √
    Evaluating this from 1 to 3 we obtain the answer. 2