HMMT 二月 2009 · CALC 赛 · 第 2 题
HMMT February 2009 — CALC Round — Problem 2
题目详情
英文原题
- [ 3 ] The differentiable function F : R → R satisfies F (0) = − 1 andd
F ( x ) = sin(sin(sin(sin( x )))) · cos(sin(sin( x ))) · cos(sin( x )) · cos( x ) .
Find F ( x ) as a function of x .dx A
解析
英文解析
- [ 3 ] The differentiable function F : R → R satisfies F (0) = − 1 andd
F ( x ) = sin(sin(sin(sin( x )))) · cos(sin(sin( x ))) · cos(sin( x )) · cos( x ) .
Find F ( x ) as a function of x .dx
Answer: − cos(sin(sin(sin( x ))))
Solution: Substituting u = sin(sin(sin( x ))), we find
∫
F ( x ) = sin( u ) du = − cos( u ) + C.
for some C . Since F (0) = 1 we find C = 0. A