HMMT 二月 2009 · CALC 赛 · 第 10 题
HMMT February 2009 — CALC Round — Problem 10
题目详情
英文原题
- [ 8 ] Let a and b be real numbers satisfying a > b > 0. Evaluate
∫
2 πdθ.1
a + b cos( θ )
Express your answer in terms of a and b .0
解析
英文解析
- [ 8 ] Let a and b be real numbers satisfying a > b > 0. Evaluate
∫
2 πdθ.1
a + b cos( θ )
Express your answer in terms of a and b .0
2 π
√
Answer:
2 2
a − b
Solution: Using the geometric series formula, we can expand the integral as follows:3
( )
∫ ∫
2 π 2 π2
1 1 b bdθ = 1 + cos( θ ) + cos ( θ ) dθ2
a + b cos( θ ) a a a
0 0
( ) ( )
∫
∞nn
2 πiθ − iθ
∑
1 be + e = dθa a 2
n =00
( )
( )
∞ n
2 n
∑2
2 π bn = dθ
2 2 na a 2
n =0
( )
2 n
To evaluate this sum, recall that C = is the n th Catalan number. The generating function 1
n +1 nnfor the Catalan numbers is
√
∞
∑
1 − 1 − 4 xn
C x = ,
2 xnn =0
)
∑ (
2 nn 1
√
and taking the derivative of x times this generating function yields x = . Thus then
1 − 4 x
2 π
√
integral evaluates to , as desired.
2 2
a − b 4