HMMT 十一月 2008 · 冲刺赛 · 第 18 题
HMMT November 2008 — Guts Round — Problem 18
题目详情
- [ 10 ] Find the coefficient of x in the expansion of
∑6
6 i
( x + 1) · xi =0
1 HARVARD-MIT NOVEMBER TOURNAMENT, 8 NOVEMBER 2008 — GUTS ROUNDst
英文原题
[ 10 ] Find the coefficient of x 6 in the expansion of
( x + 1) 6 ·
6 ∑
i =0
x i
. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .
1 st HARVARD-MIT NOVEMBER TOURNAMENT, 8 NOVEMBER 2008 — GUTS ROUND
解析
英文解析
- [ 10 ] Find the coefficient of x in the expansion of
∑6
6 i
( x + 1) · xi =0
6 i 3
Answer: 64 Each term of ( x + 1) can be multiplied by a unique power x , 0 ≤ i ≤ 6 to get a sixthdegree term. So the answer is the sum of the coefficients of the terms of ( x + 1) , which is the same as 6
substituting x = 1 into this power to get 2 = 64.6
1 HARVARD-MIT NOVEMBER TOURNAMENT, 8 SATURDAY 2008 — GUTS ROUNDst