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HMMT 二月 2008 · TEAM2 赛 · 第 3 题

HMMT February 2008 — TEAM2 Round — Problem 3

专题
Contest Math / 竞赛数学
难度
L3
来源
HMMT

题目详情

英文原题

  1. [ 35 ] By a tropical polynomial we mean a function of the formn n − 1
    p ( x ) = a x ⊕ a x ⊕ · · · ⊕ a x ⊕ a ,
    n n − 1 1 0
    where exponentiation is as defined in the previous problem.
    Let p be a tropical polynomial. Prove that
    ( )
    x + y p ( x ) + p ( y )
    p ≥
    2 2
    for all x, y ∈ R ∪ {∞} . (This means that all tropical polynomials are concave.)
解析

英文解析

  1. [ 35 ] By a tropical polynomial we mean a function of the formn n − 1
    p ( x ) = a x ⊕ a x ⊕ · · · ⊕ a x ⊕ a ,
    n n − 1 1 0
    where exponentiation is as defined in the previous problem.
    Let p be a tropical polynomial. Prove that
    ( )
    x + y p ( x ) + p ( y )
    p ≥
    2 2
    for all x, y ∈ R ∪ {∞} . (This means that all tropical polynomials are concave.)
    Solution: First, note that for any x , . . . , x , y , . . . , y , we have
    1 n 1 nmin { x + y , x + y , . . . , x + y } ≥ min { x , x , . . . , x } + min { y , y , . . . , y } .
    1 1 2 2 n n 1 2 n 1 2 n
    Indeed, suppose that x + y = min { x + y } , then x ≥ min x and y ≥ min y , and som m i i i m i i m i imin { x + y } = x + y ≥ min x + min y .
    i i i m m i i i i
    Now, let us write a tropical polynomial in a more familiar notation. We havep ( x ) = min { a + kx } .
    0 ≤ k ≤ nk
    So 1
    ( ) { ( )}
    x + y x + yp = min a + k
    2 0 ≤ k ≤ n 2 k = min { ( a + kx ) + ( a + ky ) }1
    k k
    2 0 ≤ k ≤ n
    ( )
    ≥ min { a + kx } + min { a + ky }1
    k k
    2 0 ≤ k ≤ n 0 ≤ k ≤ n = ( p ( x ) + p ( y )) .1 2