HMMT 二月 2008 · TEAM1 赛 · 第 3 题
HMMT February 2008 — TEAM1 Round — Problem 3
题目详情
英文原题
- [ 20 ] Let n > 4 be a positive integer. Determine the number of ways to walk from (0 , 0) to
( n, 2) using only up and right unit steps such that the path does not meet the lines y = x ory = x − n + 2 except at the start and at the end.
解析
英文解析
- [ 20 ] Let n > 4 be a positive integer. Determine the number of ways to walk from (0 , 0) to
( n, 2) using only up and right unit steps such that the path does not meet the lines y = x ory = x − n + 2 except at the start and at the end.
Answer: ( n − 5 n + 2)211
Solution: It is easy to see the the first two steps and the last two steps must all be right 2
steps. So we need to compute the number of walks from (2 , 0) to ( n − 2 , 0) that does not pass
( )
n − 2
through (2 , 2) and ( n − 2 , 0). There are paths from (2 , 0) to ( n − 2 , 0), and exactly two
( )2
n − 2
1 1 2
of them are invalid. So the answer is − 2 = ( n − 2)( n − 3) − 2 = ( n − 5 n + 2).
2 2 2