HMMT 二月 2008 · 冲刺赛 · 第 21 题
HMMT February 2008 — Guts Round — Problem 21
题目详情
英文原题
- [ 10 ] Let ABC be a triangle with AB = 5, BC = 4 and AC = 3. Let P and Q be squares inside ABCwith disjoint interiors such that they both have one side lying on AB . Also, the two squares each havean edge lying on a common line perpendicular to AB , and P has one vertex on AC and Q has onevertex on BC . Determine the minimum value of the sum of the areas of the two squares.
A BPQC
11 HARVARD-MIT MATHEMATICS TOURNAMENT, 23 FEBRUARY 2008 — GUTS ROUNDth 2
解析
英文解析
- [ 10 ] Let ABC be a triangle with AB = 5, BC = 4 and AC = 3. Let P and Q be squares inside ABCwith disjoint interiors such that they both have one side lying on AB . Also, the two squares each havean edge lying on a common line perpendicular to AB , and P has one vertex on AC and Q has onevertex on BC . Determine the minimum value of the sum of the areas of the two squares.
A BPQC
Answer: Let the side lengths of P and Q be a and b , respectively. Label two of the vertices of 144
P as D and E so that D lies on AB and E lies on AC , and so that DE is perpendicular to AB . The 49
triangle ADE is similar to ACB . So AD = a . Using similar arguments, we find that 3
3 a 4 b 4 + a + b + = AB = 5
4 3
a b 5 so + = .
4 3 7
Using Cauchy-Schwarz inequality, we get
( ) ( )
( )2
1 1 a b 25
2 2
a + b + ≥ + = .
2 2
4 3 4 3 49
It follows that 5
2 2144
a + b ≥ .
36 4849
Equality occurs at a = and b = .
35 35
11 HARVARD-MIT MATHEMATICS TOURNAMENT, 23 FEBRUARY 2008 — GUTS ROUNDth 2