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HMMT 二月 2008 · 冲刺赛 · 第 17 题

HMMT February 2008 — Guts Round — Problem 17

专题
Contest Math / 竞赛数学
难度
L3
来源
HMMT

题目详情

英文原题

  1. [ 9 ] Solve the equation
    √
    √
    √
    √
    √
    √
    √
    √
    √
    2008
    x + 4 x + 16 x + . . . + 4 x + 3 − x = 1 .
    Express your answer as a reduced fraction with the numerator and denominator written in their primefactorization.
    °
解析

英文解析

  1. [ 9 ] Solve the equation
    √
    √
    √
    √
    √
    √
    √
    √
    √
    2008
    x + 4 x + 16 x + . . . + 4 x + 3 − x = 1 .
    Express your answer as a reduced fraction with the numerator and denominator written in their primefactorization.
    Answer: Rewrite the equation to get 1
    4016
    √2
    √
    √
    √
    √
    √
    √
    √
    √
    2008
    x + 4 x + 16 x + . . . + 4 x + 3 = x + 1 .
    Squaring both sides yields
    √
    √
    √
    √
    2008
    4 x + . . . + 4 x + 3 = 2 x + 1 .
    Squaring again yields
    √
    √
    √
    √
    2008
    16 x + . . . + 4 x + 3 = 4 x + 1 .
    One can see that by continuing this process one gets
    √
    √
    2008
    2008
    4 x + 3 = 2 x + 1 ,
    √
    2008 − 2008
    so that 2 · 2 x = 2. Hence x = 4 . It is also easy to check that this is indeed a solution to theoriginal equation.
    °