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HMMT 二月 2008 · COMB 赛 · 第 9 题

HMMT February 2008 — COMB Round — Problem 9

专题
Contest Math / 竞赛数学
难度
L3
来源
HMMT

题目详情

英文原题

  1. [ 7 ] On an infinite chessboard (whose squares are labeled by ( x, y ), where x and y range over all integers),
    a king is placed at (0 , 0). On each turn, it has probability of 0 . 1 of moving to each of the four edgeneighboring squares, and a probability of 0 . 05 of moving to each of the four diagonally-neighboringsquares, and a probability of 0 . 4 of not moving. After 2008 turns, determine the probability that theking is on a square with both coordinates even. An exact answer is required.
解析

英文解析

  1. [ 7 ] On an infinite chessboard (whose squares are labeled by ( x, y ), where x and y range over all integers),
    a king is placed at (0 , 0). On each turn, it has probability of 0 . 1 of moving to each of the four edgeneighboring squares, and a probability of 0 . 05 of moving to each of the four diagonally-neighboringsquares, and a probability of 0 . 4 of not moving. After 2008 turns, determine the probability that theking is on a square with both coordinates even. An exact answer is required.
    1 3
    Answer: + Since only the parity of the coordinates are relevant, it is equivalent to
    2008
    4 4 · 5
    consider a situation where the king moves (1 , 0) with probability 0 . 2, moves (0 , 1) with probability 0 . 2,
    moves (1 , 1) with probability 0 . 2, and stays put with probability 0 . 4. This can be analyzed using thegenerating function
    2008
    (2 + x + y + xy )
    2008
    f ( x, y ) = (0 . 4 + 2 × 0 . 1 x + 2 × 0 . 1 y + 4 × 0 . 05 xy ) = .
    2008
    a b 5
    We wish to find the sum of the coefficients of the terms x y , where both a and b are even. Thisis simply equal to ( f (1 , 1) + f (1 , − 1) + f ( − 1 , 1) + f ( − 1 , − 1)). We have f (1 , 1) = 1 and f (1 , − 1) =1
    20084
    f ( − 1 , 1) = f ( − 1 , − 1) = 1 / 5 . Therefore, the answer is
    ( )
    1 1 3 1 3
    ( f (1 , 1) + f (1 , − 1) + f ( − 1 , 1) + f ( − 1 , − 1)) = 1 + = + .
    2008 2008
    4 4 5 4 4 · 5 3