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HMMT 二月 2007 · TEAM1 赛 · 第 7 题

HMMT February 2007 — TEAM1 Round — Problem 7

专题
Contest Math / 竞赛数学
难度
L3
来源
HMMT

题目详情

英文原题

  1. [ 25 ] Show that for positive integers n ,
    ∑
    μ ( d ) φ ( n ) = .
    d nd | n
解析

英文解析

  1. [ 25 ] Show that for positive integers n ,
    ∑
    μ ( d ) φ ( n ) = .
    d nd | n
    Solution. On the grounds of the previous problem, M¨ obius inversion with f ( k ) = φ ( k ) and g ( k ) = kgives:
    ( ) ( )
    ∑ ∑ ∑
    n n n
    ′ ′
    φ ( n ) = f ( n ) = g ( d ) μ = g μ ( d ) = μ ( d ) .
    ′ ′
    d d d
    ′ ′
    d | n d | n d | nμ ( d )
    Alternatively, one uses the convolution of the functions f ( k ) = n and g ( k ) = . The strategy is thedk k k − 1
    same as the previous convolution proof. For n = p with k a positive integer, we have φ ( n ) = p − p ,
    k k k k − 1
    while the series reduces to p · μ (1) + p · μ ( p ) /p = p − p .