HMMT 二月 2007 · TEAM1 赛 · 第 7 题
HMMT February 2007 — TEAM1 Round — Problem 7
题目详情
英文原题
- [ 25 ] Show that for positive integers n ,
∑
μ ( d ) φ ( n ) = .
d nd | n
解析
英文解析
- [ 25 ] Show that for positive integers n ,
∑
μ ( d ) φ ( n ) = .
d nd | n
Solution. On the grounds of the previous problem, M¨ obius inversion with f ( k ) = φ ( k ) and g ( k ) = kgives:
( ) ( )
∑ ∑ ∑
n n n
′ ′
φ ( n ) = f ( n ) = g ( d ) μ = g μ ( d ) = μ ( d ) .
′ ′
d d d
′ ′
d | n d | n d | nμ ( d )
Alternatively, one uses the convolution of the functions f ( k ) = n and g ( k ) = . The strategy is thedk k k − 1
same as the previous convolution proof. For n = p with k a positive integer, we have φ ( n ) = p − p ,
k k k k − 1
while the series reduces to p · μ (1) + p · μ ( p ) /p = p − p .